Monday, September 03, 2007

US Open 2007: Svetlana Kuznetsova Goes into the Quarter Final

Russian tennis star Svetlana Kuznetsova has defeated Belarusian Victoria Azarenka in their fourth round match of US Open 2007. Svetlana Kuznetsova won the match by 6-2, 6-3. Thus Kuznetsova confirmed her quarter final appearance in US Open 2007. The Belarusian could not show any resistant against the fourth seed Svetlana Kuznetsova. Victoria Azarenka looked very ordinary in the match.

The Hindu reported:
The 22-year-old Russian, who was an upset U.S. Open winner in 2004, defeated fast-rising 18-year-old Victoria Azarenka of Belarus 6-2, 6-3.
Kuznetsova will next meet Agnes Szavay of Hungary, who defeated Julia Vakulenko of Ukraine 6-4, 7-6(1) in another early fourth-round tie.

Svetlana Kuznetsova won her first and only grand slam title in US Open 2004. However, from then on she could not live up to the expectation. Svetlana Kuznetsova could manage to play in the final of French Open 2006. However, this year, Kuznetsova’s performance in WTA was consistent. The 22 year old, Svetlana Kuznetsova is now the biggest hope of the Russian people after the early exit of the defending champion Maria Sharapova from the third round. Svetlana Kuznetsova will meet Hungarian Agnes Szavay at her quarter final match.

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